Ok, my question is where can I find LED eyes for my reaper head? I don't know how to "wire" them or for that matter where to find them! Do they come "premade" for a 9V battery? Thanks to anybody who can help me out!!!



Send..more..brains

terrorworks.com

Haunted Display
http://halloweengallery.com/thumbnails.php?album=146

I would be glad to make some for you. Contact me terrorworks@gmail.com and we can work something out.

Inexpensive Flying Crank Ghost kits and much more. www.terrorworks.com

Booterbunz--Are you looking for a certain color LED? Do you just need the LED circuit or are you looking for something like the "Eyes in the Bushes" type like these: http://halloweengallery.com/thumbnails.php?album=42
(Note: this is NOT a solicitation for sales--if you need them badly and I can help you out I can put them together for you.) Crunch time!
Crunch time!

I ONLY WRITE WHAT THE VOICES TELL ME TO ......

if you need them badly and I can help you out I can put them together for you.) Crunch time!
Crunch time!

Thank you Dave, TerrorWorks has been able to help me out! Your LED eyes are pretty cool looking!




Send..more..brains

I just got into wiring some of those myself. It's really easy if you have a soldering iron. You might be able to use some of that liquid solder stuff in a tube if you don't. I've never used the stuff, but I guess it works like some sort of metallic glue. I went to Radio Shack and got a variety pack of LEDs, red and green mixed. I think there's about 16 or so in there for about $3. Then I got a pack of 9-volt battery wiring packs. 5 for $2. Next you need a pack of 270 ohm resistors, 5 for $1. I had some spare 22 gage wire and solder so I don't know what that costs. 9-volt batteries are about $10 for 4. Can probably get those cheaper at Walmart.

Here's how to wire a pair of eyes.
1. Solder the red wire from the battery pack to one end of a resistor. Works either way.
2. Then solder the other end of the resistor to the positive wire on one of the LEDs, should be the longer one.
3. Now solder a piece of wire from the negative wire on that first LED to the positive wire on the second LED. Make it as long as you need to space your eyes.
4. Solder the black wire from the battery pack to the negative wire on the second LED.
5. Plug in a battery and you're done.

***Trick or treat. Smell my feet. Give me something good to eat.***

Forgot to add that that resistor size is just for the 2 LEDs connected to one 9-volt. You should be able to wire 2 more LEDs to that set up and leave off the resistor, but I haven't tried that yet. I've been just making pairs to use in different props. You can buy different battery packs for different amounts of batteries, but you'll need to figure out what resistor to buy for the amount of batteries vs. the amount of LEDs you want to wire into one unit. I'm going to try to wire a bunch of pairs of LEDs together to one big battery pack to make a bunch of eyes to hide in the bushes. They also sell blinking LEDs so I might use some of those too.

***Trick or treat. Smell my feet. Give me something good to eat.***

I really want to wire up some eyes this year too, I'm C&P'ing this great information - thank you for this thread!

otherworldly

"In the dark shadow of the grove, on the margin of the brook, he beheld something huge, misshapen, black and towering..."

The Legend of Sleepy Hollow by Washington Irving

Q for anyone who has knowledge ofLED's. I took my FCG out of storage this year, and the little black wire somehow came out of the black part where the battery goes. It is still securely fastened to the LED's, it's just the battery end thats out, the red one is still secured if that mean anything. What to do?

_____________________
http://halloweengallery.com/index.php?cat=10049

The general formula is R=E/I
Stated a bit more specifically as (Vs-Vf)/Id

Where:
Vs is your supply voltage, for example 9 for a 9V battery
Vf is is the forward voltage of all your LED's wired in series, for example 3 LED's with a forward voltage of 2.5 would be 7.5 total
Id is the rated current of the LED in amps (typically around 20mA, so 0.02)

Thus, for the example values (9-7.5)/0.02 would give 75 ohms, so pick the next larger standard size (82 ohms in this case). Basically the (Vs-Vf) quantity is the voltage "left over" after the diodes have eaten their share that must be dissipated.

To calculate the power rating of the resistor, use P=E^2/R where E is that same "left over" voltage, and R is the ohm value of the resistor actually used. For the example values, 1.5^2/82 = 0.027 amps, so an eighth watt resistor would be plenty.

Another example: 24 volt supply, 2 LED's 3V 30mA:
R = (24-6)/.03 = 600 (so use 680)
P = (18^2/680) = 0.476 (so use a half watt resistor)